Tema: Re: Garso sistemele iki 3k lt
Autorius: Signalizacija
Data: 2009-10-04 14:26:50
Nu tai ka tas antras subas padaro? sutri\umpina bangos ilgi?


"Icetom" <kkk@kk.com> wrote in message 
news:ha58mr$up9$1@trimpas.omnitel.net...
> Statai antrą subą priešingai jam :)
> 1. 
> http://www.audioholics.com/tweaks/get-good-bass/subwoofer-placement-the-place-for-bass-part-1
> 2. 
> http://www.audioholics.com/tweaks/get-good-bass/subwoofer-connection-guide
> 3. 
> http://www.audioholics.com/tweaks/speaker-setup-guidelines/crawling-for-bass-subwoofer-placement
>
> Galima skaičiuoti tuos, ilgius, bet praktikoje viskas susives į subo 
> pastatymo vietą, krossoverio, fazės-vėlinimo nustatymą ir aišku EQ 
> (equalization-išlyginimą). Kam sau saukti galvą su šiais nustatymais, 
> apart pastatymo vietos, kai, kaip jau čia minėjau, EQ kalibravimas 
> pakankamai gerai-l. gerai tai padaro už tave ;/
>
> P.s.: mano nuomone, jūs abu klystat, kad garso banga išeina iš kambario. 
> Kiek aš suprantu, ji atsimuša  į sieną kaip ir kitos dažnių bangos. Iš 
> knygos skyriaus apie žemų atkūrimą:
> "The mechanism responsible for the resonant behavior, a perfect 
> constructive interference between sounds traveling between and among two 
> or more room boundaries, creates what are known as standing waves"
>
> "To compute the frequencies at which axial standing waves occur, simply 
> measure the distance between the walls (this is one-half wavelength of the 
> lowest resonance frequency), multiply it by 2 (to get the wavelength), and 
> divide that number into the speed of sound in whatever units the 
> measurements were done (1131 ft/s, 345 m/s). The result is the frequency 
> of the fi rst-order mode along that dimension. All higher-order modes are 
> the result of multiplying this frequency by 2, 3, 4, 5, and so on. 
> Example: A room is 22 ft long. The fi rst-order resonance occurs at 
> 1131/44 = 25.7 Hz. Higher-order resonances exist at 51.4 Hz, 77.1 Hz, 
> 102.8 Hz, and so on. Do this for the length, width, and height of the 
> room, and all of the axial modes will have been calculated"
>
> "How far the subwoofer should be from the listener is a bit different 
> because, from 150Hz down, the lower the frequency, the harder it is to 
> determine the source of the sound. As the lower limit of human hearing 
> (20Hz) is approached, it becomes nearly impossible to locate a subwoofer 
> by sound alone: the wavelengths are so long that they become 
> nondirectional, or omnidirectional. Not only does this mean the subwoofer 
> doesn’t need to be placed near the main speakers (i.e., at the front of 
> the room), it also means that it can be placed closer to the listener, if 
> that placement gives the most even frequency response." (iš čia: 
> http://www.psbspeakers.com/audio-topics/How-to-Set-Up-a-Subwoofer-Placement-Basics)
>
>
> "Signalizacija" <signalizacija.master@gmail.com> parašė naujienų 
> news:ha51lf$n6u$1@trimpas.omnitel.net...
>> gerai bandau aiskintis
>> 30Hz bangos ilgis 11.43m
>> 40Hz bangos ilgis 8,57m
>> 50Hz bangos ilgis 6,86m
>> na ir t.t.
>> ka cia galima pakeisti, kad tas galas kambary liktu?
>>
>> "Zose" <Nera@jokio.lt> wrote in message 
>> news:ha41k7$341$1@trimpas.omnitel.net...
>>> matau kad nesusipratelis kazkoks esi, toij isaiskinsiu:
>>> gali but tokia ilga banga, kad pas kaimynus jos galas atsiras.
>>> ar supranti?
>
>