Tema: Re: RAM
Autorius: amenox
Data: 2019-03-07 10:24:37
Na taip, daug teorijų, bet įstatai ir neveikia. :) Einu dar į kitus kompus 
pabandysiu pakaišiot.

"MRT"  wrote in message news:q5qjtn$ka7$1@trimpas.omnitel.net...

> Po 16 pas mane -https://1drv.ms/u/s!AuFbL6cUGTelhqcfR3VVNuojIrvENw 
> nesuprasi ten.

Matai.. Asus "irgi geri", bet Kingston'as "ne ka blogesnis"
https://www.kingston.com/datasheets/kvr800d2n6_4g.pdf

Note: The module defined in this data sheet is one of several
configurations available under this part number.
While all configurations are compatible, the DRAM combination
and/or the module height may vary from what is described here.

https://img.mysku-st.ru/uploads/images/01/56/54/2016/03/29/21a23e.jpg
chipukai su Micron'o logo .. o taviskiai tarsi Samsunginiai..

https://datasheet.iiic.cc/datasheets-0/samsung/K4T1G044QQ-HCE7.pdf
1Gb Q-die DDR2 SDRAM Specification
K4T1G044QQ-HC(L)E7 = 256Mx4 DDR2-800 5-5-5

5.0 DDR2 SDRAM Addressing
4Gb - Configuration  256Mb x16 = # of Bank 8

----

Bet cia siaip.. jau teoriniai nukrypimai ir negausiai tikslus..
Nebaisiai raukiu ... jei RAM 4GB, o chipukus po 16 kiekvienoj pusej,
tai gaunasi 4GB / 32 chipukai = po 128MB chipuke..
jei 16chipuku tik vienoj pusej - tada po 256MB chipukas..

1Gb Q-die = arba 256Mx4 arba 128Mx8 arba 64Mx16 << visur bitai
1Gb * 32chip / 8bits/byte = 4GB

pagal Kingston

512M x 64-bit 4GB (4096MB) DDR2-800 CL6
sixteen 256M x 8-bit DDR2-800 SDRAM

Cia 2*256M x 8*8-bit  ??? .. tipo Stripe kazkoks is 2chipuku :)
Kai tiesiog istatai ir veikia, ant tiek kazkaip px visa tai :))